• a) x: (-2,3) = -4,6;б) (7-х)•(х+2)=0в)-2,7• х=10,8СРОЧНО ЕТО КОНТРОЛЬНАЯ РАБОТА Только полете ответи ​

Ответы 1

  • Пошаговое объяснение:

    a) To find the midpoint of the line segment with endpoints (-2,3) and (-4,6), we can use the midpoint formula:

    Midpoint = ((-2 + (-4))/2, (3 + 6)/2)

    Midpoint = (-3, 4.5)

    Therefore, the coordinates of the midpoint are (-3, 4.5).

    б) To solve the equation (7-x)(x+2)=0, we can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero. In this case, we have:

    (7-x)(x+2)=0

    So either 7-x=0 or x+2=0.

    If 7-x=0, then x=7.

    If x+2=0, then x=-2.

    Therefore, the solutions to the equation are x=7 and x=-2.

    в) To solve the equation -2.7x=10.8, we can divide both sides by -2.7 to isolate x:

    -2.7x/(-2.7) = 10.8/(-2.7)

    x = -4

    Therefore, the solution to the equation is x = -4.

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