МНОЖЕННЯ ОДНОЧЛЕНА НА МНОГОЧЛЕН Виконай множення. a(5+ b) =. 0,1(x-y) = -c(3+a)= -na-5,5) = 2a(x+y) = -5b(b - b) = m(1 - m) = -x(2x + 5) = (-a - 4bc)(-b) = а(3+2+a) = b(2b-7)= (a + c)(d + b) = (x+y)(a + x) (2 + y)(x - 1) = = (c+b)(c-a) = (c-d)(d-c) = (x-1)(1-x) = (y - 4)(Зу - 4) = (3c+a)(2c-a) = (2-3)(²+2) = (a - b)(a - b) = (3+ c)(5-²)= (x - a)(x² + b) =

Ответ:

a(5+ b) = 5a + ab

0.1(x-y) = 0.1x - 0.1y

-c(3+a) = -3c - ac

-na-5.5 = -na - 5.5

2a(x+y) = 2ax + 2ay

-5b(b - b) = 0

m(1 - m) = m - m^2

-x(2x + 5) = -2x^2 - 5x

(-a - 4bc)(-b) = ab + 4b^2c

a(3+2+a) = 3a + 2a^2

b(2b-7) = 2b^2 - 7b

(a + c)(d + b) = ad + ab + cd + bc

(x+y)(a + x) = x^2 + xy + ax + ay

(2 + y)(x - 1) = 2x - 2 + xy - y

(c+b)(c-a) = c^2 - ac + bc - ab

(c-d)(d-c) = c^2 - 2cd + d^2

(x-1)(1-x) = -x^2 + 2x - 1

(y - 4)(y - 4) = y^2 - 8y + 16

(3c+a)(2c-a) = 6c^2 - a^2 - ac

(2-3)(2+2) = -4

(a - b)(a - b) = a^2 - 2ab + b^2

(3+ c)(5-2) = 9 + 3c

(x - a)(x^2 + b) = x^3 + bx - ax^2 - ab