Найдите tg^2a, если 4sin^2a + 9cos^2a =6

Tg6 sin3 * 2 = cos6 : 3 = 2 Ответ : 2 :D

sin2(a) +cos2(a)=14( sin2(a) +cos2(a))=4тогда 4sin2(a) +9cos2(a)=4 sin2(a) +4cos2(a)+ 5cos2(a)=4+5cos2(a)=65cos2(a) = 2tg2(a) = 1 - 1/ cos2(a) = 1- 1/(2/5)=1-5/2=-3/2