sinx+cosx=0 (решите уравнение) Товарищи,в бой!))))))

1)2sinx/2cosx/2+cos²x/2-sin²x/2=0/cos²x/2≠0tg²x/2-2tgx/2-1=0tgx/2=aa²-2a-1=0D=4+4=8a1=(2-2√2)/2=1-√2⇒tgx/2=1-√2⇒x/2=arctg(1-√2)+πn⇒x=2arctg(1-√2)+2πna2=1+√2⇒tgx/2=1+√2⇒x/2=arctg(1+√2)+πn⇒x=2arctg(1+√2)+2πn2)√2(√2/2sinx+√2/2cosx)=0√2sin(x+π/4)=0sin(x+π/4)=0x+π/4=πnx=-π/4+πnвыбирай