1. Найдите производную : у=2х^5/3 - 3/х ; у=tgx*e^x ; y=sin^3(3x/2) ; y= lnx/3 2. Найти значение производной функции

1.

(2x^5/3 - 3/x)\' = 2 * 5/3 * x^2/3 - 3 * (-2) * x^(-2) = 10/3 * x^2/3 + 6 / x^2;

 (tg(x) * e^x)\' = (tg(x))\' * e^x + tg(x) * (e^x)\' = 1/cos^2(x) * e^x + tg(x) * e^x; 

(sin^3(3x/2))\' = 3 * sin^2(3x/2) * (sin(3x/2))\' = 3 * sin^2(3x/2) * cos(3x/2) * 3/2;

 (ln(x/3))\' = 1/x * 1/3 = 1/ 3x. 

2. (y)\' = (x^3 +2sin(x))\' = 3x^2 +2cos(x).

(y(π))\' = 3 * π^2 + 2 * (-1) = 3 * π^2 - 2.