1) y=cos^3(lnx) 2) y=√sin(4x^2) 3) y=2^x*tg(x-x^2) Требуется взять производную 1) y=sin(tgx) 2)y=√tg(5x^2) 3)y= 7^x*ctg(3x^2)

1) y\' = (cos^3(ln(x))) = 3 * cos^2(ln(x)) * (-sin(ln(x)) * 1/x;

2) y\' = (√sin(4x^2))\' = 1/2 * sin^(-1/2)(4x^2) * cos(4x^2) * 8x;

3)  (y)\' = (2^x * tg(x - x^2))\' = (2^x)\' * tg(x - x^2) + 2^x * (tg(x - x^2))\' = 2^x * ln(2) * tg(x - x^2) + 2^x * 1 / cos^(x - x^2) * (1 - 2x).

1) (y)\' = cos(tg(x)) * 1 / cos^2(x);

2) (y)\' = 1/2 * (tg(5x^2))^(-1/2) * 1 / cos^2(5x^2) * 10x;

3) (y)\' = (7^x * ctg(3x^2))\' = (7^x)\' * ctg(3x^2)  + 7^x * (ctg(3x^2))\' = 7^x * ln(7) *ctg(3x^2) + 7^x * (-1 / sin^2(3x^2) * 6x.