Найти вторую производную каждой из следующих функций: 1) у=5x^+3x-1 2)y=7x^3+5x^-3x+2 3)1.2x^4+0.5x^3+8 4)y=(x^-2)2 5)=(x^+3x)3

f(x)\' = (x^3 – 3x^2 + 5)’ = (x^3)’ – (3x^2)’ + (5)’ = 3 * x^(3 – 1) – 3 * 2 * x^(2 - 1) – 0 = 3 * x^2 – 6 * x^1 = 3x^2 – 6x.

f(x)\' = ((x^2 + 1) / (x^2 – 1))’ = ((x^2 + 1)’ * (x^2 – 1) - (x^2 + 1) * (x^2 – 1)’) / (x^2 – 1)^2 =

f(x)\' = (-√x)’ = (-1 * √x)’ = (-1) * (√x)’ = (-1) * (1 / 2√x) = -1 / 2√x.

f(x)\' = ((x^3 + 1)^4)’ = (x^3 + 1)’ * ((x^3 + 1)^4)’ = ((x^3)’ + (1)’) * ((x^3 + 1)^4)’ = (3x^2 + 0) * 4 * (x^3 + 1)^3 = 12x^2 * (x^3 + 1)^3.

f(x)\' = (2 * (5x + 4)^(-1))’ = 2 * (5x + 4)’ * (5x + 4)^(-1)’ = 2 * ((5x)’ + (4)’) * (5x + 4)^(-1)’ = 2 * (5 + 0)’ * (-1) * (5x + 4)^(-2) = -10 * (5x + 4)^(-2) = -10 / (5x + 4)^2.

f(x)\' = ((-4x^3 + 1)^4 - (2 - x)^5)’ = ((-4x^3 + 1)^4)’ – ((2 - x)^5)’) = ((-4x^3 + 1)’ * (-4x^3 + 1)^4)’ – (2 - x)’ * ((2 - x)^5)’) = ((-4x^3)’ + (1)’) * (-4x^3 + 1)^4)’ – ((2)’ – (x)’) * ((2 - x)^5)’) = (-4 * 3 * x^2 + 0) * 4 * (-4x^3 + 1)^3 – (0 – 1) * 5 * (2 – x)^4 = -24x^2 * (-4x^3 + 1)^3 + 5 * (2 – x)^4.