Дано:CxOyHzω (C) = 64,9%ω (O) = 21,6%ω (H) = 13,5%D возд. (CxOyHz) = 2,55
Найти:CxOyHz - ?
1) M (CxOyHz) = D возд. (CxOyHz) * M (возд.) = 2,55 * 29 = 74 г/моль;2) Mr (CxOyHz) = M (CxOyHz) = 74;3) x = (ω (C) * Mr (CxOyHz)) / (Ar (C) * 100%) = (64,9% * 74) / (12 * 100%) = 4;4) y = (ω (O) * Mr (CxOyHz)) / (Ar (O) * 100%) = (21,6% * 74) / (16 * 100%) = 1;5) z = (ω (H) * Mr (CxOyHz)) / (Ar (H) * 100%) = (13,5% * 74) / (1 * 100%) = 10;6) C4OH10;7) https://bit.ly/33QKjBV
Ответ: Неизвестное вещество - C4OH10.
Автор:
louisydvrДобавить свой ответ